Java: How to test if individual characters are even or odd? -

in java, how test if character or odd digit?

here have far:

import java.util.scanner;  public class oddoreven{    public static void main(string args[]){        scanner input = new scanner(system.in);            int number, digit1, digit2, digit3;            system.out.print( "enter three-digit number: " );// prompt           number = input.nextint(); // read number            // determine 3 digits           digit1 = number / 100;           digit2 = number % 100 / 10;           digit3 = number % 100 % 10;            if (digit1 % 2 == 0 && digit2 % 2 == 0 && digit3 % 2 == 0);               system.out.println( "this number contains digits.");            if (digit1 % 2 != 0 && digit2 % 2 == 0 && digit3 % 2 == 0);               system.out.println("this number contains both odd , digits.");            if (digit1 % 2 != 0 && digit2 % 2 != 0 && digit3 % 2 == 0 );             system.out.println("this number contains both odd , digits.");               if (digit1 % 2 == 0  && digit2 % 2 != 0 && digit3 % 2 == 0 );             system.out.println("this number contains both odd , digits.");             if (digit1 % 2 == 0  && digit2 % 2 != 0 && digit3 % 2 != 0);             system.out.println("this number contains both odd , digits.");             if (digit1 % 2 != 0 && digit2 % 2 != 0 && digit3 % 2 != 0);             system.out.println("this number contains odd digits.");    } } 

if number working int (or similar primitive type long) can this

int num = // while (num != 0) {     int digit = num % 10;     system.out.println(digit + " " + (digit % 2 == 0 ? "even" : "odd"));     num /= 10; } 

this iterate on digits right left.