regex - python return matching and non-matching patterns of string -

i split string parts match regexp pattern , parts not match list.

for example

import re string = 'my_file_10' pattern = r'\d+$' #  know matching pattern can obtained : m = re.search(pattern, string).group() print m '10' #  final result should following ['my_file_', '10'] 

put parenthesis around pattern make capturing group, use re.split() produce list of matching , non-matching elements:

pattern = r'(\d+$)' re.split(pattern, string) 

demo:

>>> import re >>> string = 'my_file_10' >>> pattern = r'(\d+$)' >>> re.split(pattern, string) ['my_file_', '10', ''] 

because splitting on digits @ end of string, empty string included.

if ever expect one match, @ end of string (which $ in pattern forces here), use m.start() method obtain index slice input string:

pattern = r'\d+$' match = re.search(pattern, string) not_matched, matched = string[:match.start()], match.group() 

this returns:

>>> pattern = r'\d+$' >>> match = re.search(pattern, string) >>> string[:match.start()], match.group() ('my_file_', '10')