Converting long to binary in Java gives 31 bits? -

i understand unix time should 32 bit (4 byte) value. calculate current unix time, i'm using following:

long time = (system.currenttimemillis())/1000;

this works fine - same value when on unix command shell: "date +%s".

i want represent in binary, though. tried this:

system.out.println(long.tobinarystring(time));

however, 31 bits, not 32 have expected. missing?

thanks!

tim

the leading zeros aren't being displayed. try this:

long l = -1; system.out.println(long.tobinarystring(l));

or:

long l = long.min_value; system.out.println(long.tobinarystring(l));

or:

long l = -2112; system.out.println(long.tobinarystring(l));

you should see 64 bits. (long in java 64 bits, not 32)

i hope helps.

edit:

if want string representation of 32 bits leading zeros, of number of things. 1 is:

int = 42; string result = string.format("%32s", integer.tobinarystring(i)).replace(' ', '0'); system.out.println(result);

another is:

int = 42; string result = string.format("%032d", integer.parseint(integer.tobinarystring(i))); system.out.println(result);

My