ios - How to Sorting Mutable Array of NSNumbers using for Loop in Objective C? -

i tried this, not successful. can 1 sort problem?

 nsnumber *num1= [nsnumber numberwithint:5];     nsnumber *num2= [nsnumber numberwithint:3];     nsnumber *num3= [nsnumber numberwithint:7];     nsnumber *num4= [nsnumber numberwithint:9];     nsnumber *num5= [nsnumber numberwithint:2];        nsmutablearray *array =[nsmutablearray arraywithobjects:num1,num2,num3,num4,num5, nil];      int numlength = [array count];      int tempvalue;      (int = 0; < numlength; i++)     {         for(int j = 0; j < numlength; j++)         {             nsnumber *temp=[array objectatindex:i];             int first =[temp integervalue];              nsnumber *temp1=[array objectatindex:j+1];             int second =[temp1 integervalue];              if(first > second)              {                 tempvalue = second;                  [array replaceobjectatindex:j+1 withobject:temp];                 [array replaceobjectatindex:i withobject:temp1];              }         }     }      nslog(@"array %@", array); 

this code in viewdidload...

thanks

try this, works indeed:

nsmutablearray *_array = [nsmutablearray array]; (int = 0; < 5; i++) { [_array addobject:@(arc4random()%10)]; }  nslog(@"random: %@", _array);  (int = 0; < _array.count; i++) {     for(int j = i; j < _array.count; j++) {         if (i != j) {             nsinteger _first = [[_array objectatindex:i] integervalue];             nsinteger _second = [[_array objectatindex:j] integervalue];             if (_second < _first) {                 [_array exchangeobjectatindex:i withobjectatindex:j];             }         }     } }  nslog(@"sorted : %@", _array); 

note: way sort array's elements highly inefficient, recommended use educational purpose.