android - Calculating http overhead and headers -

i wondering if provide me on calculating overhead when requesting data via androidhttpclient get/post requests.

why ask? developed app shows different traffic usage when calculating payload , internet provider stats. put, data sent/received app 6mb, provider shows 16. that's > 200%.

since communication done via 1 function, can track payload size, , additional size must overhead. big, or i'm missing something? here function:

public byte[] get(final string url, int timeout) throws clientprotocolexception, ioexception {          uri uri;         try {             uri = new uri(url);         } catch (urisyntaxexception e) {             lasterror = error_url;             e.printstacktrace();             return null;         }          out += uri.tostring().length();          final httpget = new httpget(uri);         httpconnectionparams.setsotimeout(httpparameters, timeout);         httpconnectionparams.setconnectiontimeout(httpparameters, timeout);         get.setparams(httpparameters);          httpresponse responce;         final long st = system.currenttimemillis();         responce = client.execute(get, localcontext);         ping = (int) (system.currenttimemillis() - st);          inputstream = responce.getentity().getcontent();          byte[] data = inputstreamtobytearray(is);         responce.getentity().consumecontent();         in += data.length;         lasterror = error_success;          return data;      } 

ipoverhead = 26 bytes; tcpoverhead = 20 bytes;

and http comes in, how measure it's overhead?

any ideas?

http's overhead made of status line + headers.
using android's apache httpresponse allows 1 status line , headers (using getstatusline , getallheaders(), in parsed way, not in raw text. status line , headers uniformly defined (by rfc2616 §6.1 , §4.2 respectively), may have arbitrary number of (non-parsed) whitespace, can roughly determine overhead here.

unless using api or raw android sockets (which require implement own http handling), you're half there.