php - If statement in variable -

i've seen many posts problems couldn't find right answer worked out. problem have code says if ... empty, make variable ... (see code below). variable form , in form have things name, message etc. want placeholder of name, if user logged in name, saved in database. code:

    $action = isset($_post["action"]) ? $_post["action"] : ""; if (empty($action)) {      // send contact form html     $output = "<div style='display:none'>     <div class='contact-top'></div>     <div class='contact-content'>         <h1 class='contact-title'>stuur een bericht voor hulp:</h1>         <div class='contact-loading' style='display:none'></div>         <div class='contact-message' style='display:none'></div>         <br><br><form action='#' style='display:none'>             <input type='text' id='contact-name' class='contact-input' name='name' tabindex='1001' placeholder='naam*' /><br><br>             <input type='text' id='contact-email' class='contact-input' name='email' tabindex='1002' placeholder='email*' /><br><br>"; 

and want doesn't work:

<input type='text' id='contact-name' class='contact-input' name='name' tabindex='1001' placeholder=', " if (logged_in() === true) {echo $user_data["name"] } else { echo 'naam'; } " ,' /><br><br> 

hope can help, in advance,

paul

(naam = name in language)

you forgot surround if in <?php tags

 <input type='text' id='contact-name' class='contact-input' name='name' tabindex='1001' placeholder="<?php  if (logged_in() === true) { echo $user_data["name"]; } else { echo 'naam'; } ?>" /><br><br> 

ps conditions not working inside strings, if need outside of html template, need before string:

$name = 'naam'; if (logged_in() === true) { $name = $user_data["name"]; }      $html = "<input type='text' id='contact-name' class='contact-input' name='name' tabindex='1001' placeholder="{$name}" /><br><br>";