regex - Backward slash missing from substitution in Scala -


i need construct complex strings , reason use """(triple quotes) delimiters string , regexps in scala.

in examples, such this:

"""foo""".r.replaceallin("foo", m => """backslash\andsometext""") // result = """backslashandsometext""" // where's backslash?

the backslash gone form result.

what reason this? shouldn't strings wrapped in """ perform no escaping whatsoever??

you're supposed quote replacement string this way:

scala> import util.matching._ import util.matching._  scala> """foo""".r.replaceallin("foo", m => regex quotereplacement """backslash\andsometext""") res2: string = backslash\andsometext

counter-example:

scala> "f(oo)".r.replaceallin("foo", m => """backslash$1\$andsometext""") res3: string = backslashoo$andsometext

so dollar means group , backslash means escape dollar.


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