SQL Query is only selecting 2 out of 4 records - MySQL Workbench -


trying select 4 fund names , relating contacts. however, 2 being selected. want able select 4 funds regardless if have associated contact names.

below sql:

select mutual_fund_name, concat(contact_first_name,' ',contact_last_name)   mutual_fund mf, contact c, mutual_fund_has_contact mfhc, institution i,  institution_has_mutual_fund ihmf  mf.mutual_fund_id = mfhc.mutual_fund_id        , c.contact_id = mfhc.contact_id        , ihmf.mutual_fund_id = mf.mutual_fund_id        , i.institution_id = ihmf.institution_id        , mf.mutual_fund_name            in ('vanguard balanced index fund',                'vanguard consumer discretionary index fund',               'vanguard extended market index fund',                'vanguard growth index fund')  order mutual_fund_name;

how funds contacts (regardless if fund has any) return in sql statement?

i'm not sure why need explicit left outer joins. should sufficient.

select mutual_fund_name, concat(contact_first_name,' ',contact_last_name)   mutual_fund mf     left join mutual_fund_has_contact mfhc on mf.mutual_fund_id = mfhc.mutual_fund_id     left join contact c on c.contact_id = mfhc.contact_id      left join institution on i.institution_id = ihmf.institution_id     left join institution_has_mutual_fund ihmf on ihmf.mutual_fund_id = mf.mutual_fund_id mf.mutual_fund_name in ('vanguard balanced index fund',      'vanguard consumer discretionary index fund',     'vanguard extended market index fund',      'vanguard growth index fund') order mutual_fund_name;

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