How to remove multiple root tags in XML using XSLT? -

my xml looks like:

<payusw2r>   <g_employee1>     ..     . </g_employee1>  </payusw2r> <payusw2r>  <g_employee2>     ..     . </g_employee2>  </payusw2r> 

i want make formed xml follows:

<payusw2r>   <g_employee1>     ..     . </g_employee1> <g_employee2>     ..     . </g_employee2>   </payusw2r> 

basically want remove root tags < payusw2r >. can achieve using xslt? please provide here.

since xml input xslt needs well-formed, you'll have wrap instance in temporary root element. how depend on how you're running xslt. simple concatenating new start/end tags existing xml.

what should end this:

<temp>     <payusw2r>           <g_employee1>             ..             .         </g_employee1>      </payusw2r>     <payusw2r>          <g_employee2>             ..             .         </g_employee2>      </payusw2r>     </temp> 

then xslt this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">     <xsl:output indent="yes"/>     <xsl:strip-space elements="*"/>      <xsl:template match="/*">         <xsl:apply-templates select="*[1]"/>     </xsl:template>      <xsl:template match="/*/*[1]">         <xsl:copy>             <xsl:copy-of select="@*|node()|following-sibling::*/*"/>         </xsl:copy>             </xsl:template>  </xsl:stylesheet> 

this result in output:

<payusw2r>    <g_employee1>             ..             .         </g_employee1>    <g_employee2>             ..             .         </g_employee2> </payusw2r>