sql - MySQL Count if the value has not appeared before -


here table of users, carts, , time. user can have multiple carts. anonymous users have userid = 1000; identified user has id different 1000.

all cartids unique.

+------------+-------------+----------------------+ | userid     | cartid      | time                 |  +------------+-------------+----------------------+ | 7650       | 231         | 2014-08-27 13:41:02  | +------------+-------------+----------------------+ | 7632       | 221         | 2014-08-27 13:42:02  | +------------+-------------+----------------------+ | 7650       | 289         | 2014-08-27 14:13:02  | +------------+-------------+----------------------+ | 1000       | 321         | 2014-08-27 14:41:02  | +------------+-------------+----------------------+ | 7650       | 500         | 2014-08-27 17:41:02  |

i interested in calculating number of distinct identified users hour of day.

i tried following, cannot keep record of ids entered before when group them hour(date).

count( distinct (case when userid <> 1000 userid end)) numselfidusers

for output, want like:

+------------+-------------+----------------------+ | date       | hourofday   | numselfidusers       |  +------------+-------------+----------------------+ | 2014-08-27 | 13          |  2                   | +------------+-------------+----------------------+ | 2014-08-27 | 14          |  0                   | +------------+-------------+----------------------+ | 2014-08-27 | 17          |  0                   | +------------+-------------+----------------------+

please let me know if there questions. in advance help.

i think want this:

select date(time), hour(time),        count(distinct case when userid <> 1000 userid end) numselfidusers usercarts date(time) = '2014-08-27' group date(time), hour(time) order 1, 2;

this looks similar have in query. i'm not sure why version wouldn't work.

edit:

you seem want times 0 counts. bit more challenging, can this:

select d.dt, h.hr, count(distinct case when userid <> 1000 userid end)  (select distinct date(time) dt usercarts dt in range) d cross join      (select 0 hr union select 1 union select 2 union select 3 union . . .       select 23      ) h left join      usercart uc      on date(uc.time) = d.dt , hour(uc.time) = h.hr;

the . . . put in rest of numbers 3 23.

edit ii:

i suspect looking first time user appears. if so, try this:

select date(firsttime), hour(firsttime), count(*) numfirstusers (select userid, min(time) firsttime       usercarts       userid <> 1000       group userid      ) u group date(firsttime), hour(firsttime) order 1, 2;

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