mysql - Display the Object with the most equal entries -


hi want display country(land in german) haves museums.

my table looks like:

+-----------+----------------------+-------------------+--------------------------+---------------+ | museumsnr | name                 | stadt             | land                     | hauptstadt    | +-----------+----------------------+-------------------+--------------------------+---------------+ |         1 | museum of modern art | new york          | united states of america | washington dc | |         2 | kunstmuseum          | bern              | schweiz                  | bern          | |         3 | musée picasso        | paris             | frankreich               | paris         | |         4 | städel               | frankfurt main | deutschland              | berlin        | |         5 | museum ludwig        | köln              | deutschland              | berlin        | +-----------+----------------------+-------------------+--------------------------+---------------+

so desired output should be:

+--------------------------+------+ | land                     |anzahl| +--------------------------+------+ | deutschland              |    2 | +--------------------------+------+

this i´ve tried:

select land, count(name) name  museum order name desc;

the output:

+--------------------------+------+ | land                     | name | +--------------------------+------+ | united states of america |    5 | +--------------------------+------+

thanks in advance help!

select land, count(*) anzahl      yourtable      group land      order anzahl      desc limit 1;`

only tested in postgresql, should close enough in mysql.


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