c++ - Copy from hex character array to char * type -

i have global hex character array :

static char data[9] =  {0x01, 0xf2, 0x01, 0x02, 0x05, 0xff, 0xfe, 0x00, 0x11}; 

i want copy buffer character array passed main()

void getbuffer (char *buffer) {    // how copy 'data' 'buffer' }  int main()  {     char *out = new char[9];    getbuffer (out);  } 

tried memcpy, strcpy didnt work. looks have format string somehow copying ?? doing in standard c++ can use std::string related features well.

memcpy work fine, use implementation.

#include <string.h> #include <stdio.h>  static unsigned char data[9] = {0x01, 0xf2, 0x01, 0x02, 0x05, 0xff, 0xfe, 0x00, 0x11};  void    getbuffer(unsigned char *buffer) {     memcpy(buffer, data, sizeof(data)); }  int     main(int argc, char const** argv) {     unsigned char   *out = new unsigned char[sizeof(data)];     unsigned int    = 0;      getbuffer(out);     while (i < sizeof(data))     {         printf("0x%x|", out[i]);         = + 1;     }     printf("\n");     (void)argc;     (void)argv;     return (0); } 

if have 0xf2 in array it's unsigned char array.

good luck :)