php - How to make a sub connection to mysql? -


i have config file.

<?php $s_ipserver1 = "10.0.0.101"; $db_porta1    = "3306"; $db_user1     = "user"; $db_password1 = "123456"; $db_name1     = "name";  $s_ipserver2 = "xxx.xxx.xxx.xxx"; $db_porta2    = "3306"; $db_user2     = "user"; $db_password2 = "123456"; $db_name2     = "name";  $s_ipserver3 = "xxx.xxx.xxx.xxx"; $db_porta3    = "3306"; $db_user3     = "user"; $db_password3 = "123456"; $db_name3     = "name"; ?>

and want convert this.

<?php  $dbl = "1";// que servidor é este? 1, 2 ou 3.  $s_ipserver1 = "10.0.0.101"; $db_porta1    = "3306"; $db_user1     = "user"; $db_password1 = "123456"; $db_name1     = "name";  $s_ipserver2 = "xxx.xxx.xxx.xxx"; $db_porta2    = "3306"; $db_user2     = "user"; $db_password2 = "123456"; $db_name2     = "name";  $s_ipserver3 = "xxx.xxx.xxx.xxx"; $db_porta3    = "3306"; $db_user3     = "user"; $db_password3 = "123456"; $db_name3     = "name";  $s_ipserver  = "$s_ipserver$dbl"; $db_porta    = "$db_porta$dbl"; $db_user     = "$db_user$dbl"; $db_password = "$db_password$dbl"; $db_name     = "$db_name$dbl"; ?>

this 1 of connection files. 

<?php include_once("/pasta/config.php"); $db_host1     = "$s_ipserver1:$db_porta1"; $db_link1     = mysql_connect($db_host1, $db_user1, $db_password1) or die (mysql_error ()); $db_connect1  = mysql_select_db($db_name1, $db_link1);

?>

and need this.

<?php include_once("/pasta/config.php"); $db_host      = "$s_ipserver:$db_porta"; $db_link      = mysql_connect($db_host, $db_user, $db_password) or die (mysql_error ()); $db_connect   = mysql_select_db($db_name, $db_link); ?>

where mistake. original files working perfectly.

why not use array syntax connexion variables ?

$connexion[1]=['server'=>'10.0.0.101','port'=>'3306','user'=>'user','password'=>'123456','dbname'=>'name'];

or

$s_ipserver[1] = "10.0.0.101"; $db_porta[1]    = "3306"; $db_user[1]     = "user"; $db_password[1] = "123456"; $db_name[1]     = "name";

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