c - gcc saying "assignment from incompatible pointer type [enabled by default] -

ok keep getting error:

$ gcc -wall -g translate.c support.c scanner.c -o translate translate.c: in function ‘main’: translate.c:22:16: warning: assignment incompatible pointer type [enabled default]      dictionary = createarray(count);             ^ support.c: in function ‘readtokens’: support.c:66:18: warning: assignment incompatible pointer type [enabled default]          a[count] = token;               ^ 

and don't know why.

here's main function:

#include <stdio.h> #include <stdlib.h> #include <string.h> #include "support.h"  int main(int argc, char** argv) {     int i;     int count;     char** dictionary;      if (argc != 3) {         printf("need 2 arguments!\n");         exit(-1);     }      count = counttokens(argv[1]);     printf("there %d tokens , strings\n", count);      dictionary = createarray(count);      readtokens(argv[1], dictionary);      printf("the dictionary:\n");     (i = 0; < count; ++i) {         printf("%s\n", dictionary[i]);     }     return 0; } 

and create arrays function:

char* createarray(int count) {     char* a;     = malloc(sizeof(char*) * count);     if (a == 0) {         fprintf(stderr, "memory allocation failed\n");         exit(1);     }      return a; } 

and header

char * createarray(int);

i have no idea how go away. i've tried taking away , adding asteriks , changing 1 equal signs two, it's not working. 2nd year cs student, first year in c. appreciated million times over. thanks!

your createarray functions declared , implement mistake. need array of char pointers, of type (char **), create , return such array:

char** createarray(int count) {     char** a;     = malloc(sizeof(char*) * count);     if (a == 0) {         fprintf(stderr, "memory allocation failed\n");         exit(1);     }      return a; }